What are the solutions to the equation 12x^2-9=-12 ?

The solutions to the equation 12x^2-9=-12 are x= 1/2 i,x=-1/2 i

Find the zeros of 12x^2-9=-12

The zeros of 12x^2-9=-12 are x= 1/2 i,x=-1/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 9 = - 12

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

12 x^{2} - 9 = - 12

Move

9

to the right side

12 x^{2} = - 3

Divide both sides by

12

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

16 w^{2} + 8 w + 1

\frac{( x + 12 ) ( x - 4 )}{x - 1} \geq 0

64 w^{2} + 96 w + 36 = 0

\frac{a ^{- 4} b ^{4}}{4 a ^{0} b ^{- 4}}

0.01 = (0.000001) (64) (256 - x)

What are the solutions to the equation 12x^2-9=-12 ?
The solutions to the equation 12x^2-9=-12 are x= 1/2 i,x=-1/2 i
Find the zeros of 12x^2-9=-12
The zeros of 12x^2-9=-12 are x= 1/2 i,x=-1/2 i