What is ((x+12)(x-4))/(x-1)>= 0 ?

The solution to ((x+12)(x-4))/(x-1)>= 0 is -12 = 4

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((x+12)(x-4))/(x-1)>= 0

\frac{( x + 12 ) ( x - 4 )}{x - 1} \geq 0

- 12 \leq x < 1 or x \geq 4

Interval Notation

[- 12, 1) \cup [4, \infty)

Solution steps

\frac{( x + 12 ) ( x - 4 )}{x - 1} \geq 0

Identify the intervals

- 12 \leq x < 1 or x \geq 4

64 w^{2} + 96 w + 36 = 0

\frac{a ^{- 4} b ^{4}}{4 a ^{0} b ^{- 4}}

0.01 = (0.000001) (64) (256 - x)

- \frac{70}{3} + 10

26 + 324

What is ((x+12)(x-4))/(x-1)>= 0 ?
The solution to ((x+12)(x-4))/(x-1)>= 0 is -12<= x<1\lor x>= 4