What is factor (x^3+12)^2-16 ?

The solution to factor (x^3+12)^2-16 is (x^3+16)(x+2)(x^2-2x+4)

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factor (x^3+12)^2-16

factor

(x^{3} + 12)^{2} - 16

(x^{3} + 16) (x + 2) (x^{2} - 2 x + 4)

Solution steps

(x^{3} + 12)^{2} - 16

Factor the number:

16 = 4^{2}

= (x^{3} + 12)^{2} - 4^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{3} + 12)^{2} - 4^{2} = ((x^{3} + 12) + 4) ((x^{3} + 12) - 4)

= ((x^{3} + 12) + 4) ((x^{3} + 12) - 4)

Simplify

((x^{3} + 12) + 4) ((x^{3} + 12) - 4) : (x^{3} + 16) (x^{3} + 8)

= (x^{3} + 16) (x^{3} + 8)

Factor

x^{3} + 8 : (x + 2) (x^{2} - 2 x + 4)

= (x^{3} + 16) (x + 2) (x^{2} - 2 x + 4)

∣ 5 w + 15 ∣ = 0

36 r s^{2} - 108 r^{2} s^{3}

7 x^{2} - 5 x - 1 = 0

h - 8 > 4 h + 5

\frac{x}{x + 1} > 3

What is factor (x^3+12)^2-16 ?
The solution to factor (x^3+12)^2-16 is (x^3+16)(x+2)(x^2-2x+4)