What are the solutions to the equation 4x^2+15x+13=0 ?

The solutions to the equation 4x^2+15x+13=0 are x=(-15+sqrt(17))/8 ,x=(-15-sqrt(17))/8

Find the zeros of 4x^2+15x+13=0

The zeros of 4x^2+15x+13=0 are x=(-15+sqrt(17))/8 ,x=(-15-sqrt(17))/8

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4 x^{2} + 15 x + 13 = 0

x = \frac{- 15 + 17}{8}, x = \frac{- 15 - 17}{8}

Decimal Notation

x = - 1.35961 \dots, x = - 2.39038 \dots

Solution steps

4 x^{2} + 15 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 4 \cdot 13}{2 \cdot 4}

1 5^{2} - 4 \cdot 4 \cdot 13 = 17

x_{1, 2} = \frac{- 15 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 15 + 17}{2 \cdot 4}, x_{2} = \frac{- 15 - 17}{2 \cdot 4}

x = \frac{- 15 + 17}{2 \cdot 4} : \frac{- 15 + 17}{8}

x = \frac{- 15 - 17}{2 \cdot 4} : \frac{- 15 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 15 + 17}{8}, x = \frac{- 15 - 17}{8}

9 m^{2} - 66 m + 21

\frac{6 - 2 i}{- 7 + i}

(\frac{5}{2})^{2}

81 a^{2} + 36 a + 4

15 p^{2} + 80 = - 80 p

What are the solutions to the equation 4x^2+15x+13=0 ?
The solutions to the equation 4x^2+15x+13=0 are x=(-15+sqrt(17))/8 ,x=(-15-sqrt(17))/8
Find the zeros of 4x^2+15x+13=0
The zeros of 4x^2+15x+13=0 are x=(-15+sqrt(17))/8 ,x=(-15-sqrt(17))/8