What is 3/5 (4k-1)>= 5/3 (3k-2) ?

The solution to 3/5 (4k-1)>= 5/3 (3k-2) is k<= 41/39

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3/5 (4k-1)>= 5/3 (3k-2)

\frac{3}{5} (4 k - 1) \geq \frac{5}{3} (3 k - 2)

k \leq \frac{41}{39}

Interval Notation

(- \infty, \frac{41}{39}]

Decimal Notation

k \leq 1.05128 \dots

Solution steps

\frac{3}{5} (4 k - 1) \geq \frac{5}{3} (3 k - 2)

Expand

\frac{3}{5} (4 k - 1) : \frac{12}{5} k - \frac{3}{5}

Expand

\frac{5}{3} (3 k - 2) : 5 k - \frac{10}{3}

\frac{12}{5} k - \frac{3}{5} \geq 5 k - \frac{10}{3}

Move

\frac{3}{5}

to the right side

\frac{12}{5} k \geq 5 k - \frac{41}{15}

Move

5 k

to the left side

- \frac{13}{5} k \geq - \frac{41}{15}

Multiply both sides by

- 1

\frac{13}{5} k \leq \frac{41}{15}

Multiply both sides by

5

13 k \leq \frac{41}{3}

Divide both sides by

13

k \leq \frac{41}{39}

x^{3} + 7 x^{2} + 9 x + 63

\frac{1}{0.00024}

n^{2} - 2 n - 3 = 0

- 3 p^{2} - 10 p - 3

5 (10 - 3)

What is 3/5 (4k-1)>= 5/3 (3k-2) ?
The solution to 3/5 (4k-1)>= 5/3 (3k-2) is k<= 41/39