What are the solutions to the equation (x+2)^2=10 ?

The solutions to the equation (x+2)^2=10 are x=sqrt(10)-2,x=-sqrt(10)-2

Find the zeros of (x+2)^2=10

The zeros of (x+2)^2=10 are x=sqrt(10)-2,x=-sqrt(10)-2

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(x + 2)^{2} = 10

x = 10 - 2, x = - 10 - 2

Decimal Notation

x = 1.16227 \dots, x = - 5.16227 \dots

Solution steps

(x + 2)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 10 : x = 10 - 2

Solve

x + 2 = - 10 : x = - 10 - 2

The solutions to the quadratic equation are:

x = 10 - 2, x = - 10 - 2

- x^{2} + x = 2 x^{2} + x

\frac{a ^{- 2}}{2 a b ^{0}}

3 x + 2 = 2

5 (4)^{\frac{1}{4}} + 15 (4)^{\frac{1}{2}} + 3

f (y) = y^{2} - 12

What are the solutions to the equation (x+2)^2=10 ?
The solutions to the equation (x+2)^2=10 are x=sqrt(10)-2,x=-sqrt(10)-2
Find the zeros of (x+2)^2=10
The zeros of (x+2)^2=10 are x=sqrt(10)-2,x=-sqrt(10)-2