What are the solutions to the equation (5x-3)^2=49x^2 ?

The solutions to the equation (5x-3)^2=49x^2 are x=-3/2 ,x= 1/4

Find the zeros of (5x-3)^2=49x^2

The zeros of (5x-3)^2=49x^2 are x=-3/2 ,x= 1/4

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(5 x - 3)^{2} = 49 x^{2}

x = - \frac{3}{2}, x = \frac{1}{4}

Decimal Notation

x = - 1.5, x = 0.25

Solution steps

(5 x - 3)^{2} = 49 x^{2}

Expand

(5 x - 3)^{2} : 25 x^{2} - 30 x + 9

25 x^{2} - 30 x + 9 = 49 x^{2}

Move

49 x^{2}

to the left side

- 24 x^{2} - 30 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 ( - 24 ) \cdot 9}{2 ( - 24 )}

(- 30)^{2} - 4 (- 24) \cdot 9 = 42

x_{1, 2} = \frac{- ( - 30 ) \pm 42}{2 ( - 24 )}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 42}{2 ( - 24 )}, x_{2} = \frac{- ( - 30 ) - 42}{2 ( - 24 )}

x = \frac{- ( - 30 ) + 42}{2 ( - 24 )} : - \frac{3}{2}

x = \frac{- ( - 30 ) - 42}{2 ( - 24 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{1}{4}

x^{2} + 6 x + 19 = 0

10 + 9 j \geq 1

2 = \frac{2 v}{7} - 8

3 + 9 x = 11 x - 7

x^{2} + 9 x + 35 = 0

What are the solutions to the equation (5x-3)^2=49x^2 ?
The solutions to the equation (5x-3)^2=49x^2 are x=-3/2 ,x= 1/4
Find the zeros of (5x-3)^2=49x^2
The zeros of (5x-3)^2=49x^2 are x=-3/2 ,x= 1/4