What are the solutions to the equation -1=(x+4)(x+6) ?

The solutions to the equation -1=(x+4)(x+6) are x=-5

Find the zeros of -1=(x+4)(x+6)

The zeros of -1=(x+4)(x+6) are x=-5

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- 1 = (x + 4) (x + 6)

x = - 5

Solution steps

- 1 = (x + 4) (x + 6)

Expand

(x + 4) (x + 6) : x^{2} + 10 x + 24

- 1 = x^{2} + 10 x + 24

Switch sides

x^{2} + 10 x + 24 = - 1

Move

1

to the left side

x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

x = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

(\frac{1}{2} + \frac{1}{8} + \frac{1}{32} + \frac{1}{256} + \frac{1}{512}) \cdot 1024

6 x^{2} + 3 x - 3 = 0

(9 n^{4})^{\frac{1}{2}}

1 2^{2} + 1 0^{2} = x^{2}

8 x + (- 5 x - 9) = 3 x + [- 5 x - (x + 3)]

What are the solutions to the equation -1=(x+4)(x+6) ?
The solutions to the equation -1=(x+4)(x+6) are x=-5
Find the zeros of -1=(x+4)(x+6)
The zeros of -1=(x+4)(x+6) are x=-5