What are the solutions to the equation 49r^2-4=0 ?

The solutions to the equation 49r^2-4=0 are r= 2/7 ,r=-2/7

Find the zeros of 49r^2-4=0

The zeros of 49r^2-4=0 are r= 2/7 ,r=-2/7

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49 r^{2} - 4 = 0

r = \frac{2}{7}, r = - \frac{2}{7}

Decimal Notation

r = 0.28571 \dots, r = - 0.28571 \dots

Solution steps

49 r^{2} - 4 = 0

Move

4

to the right side

49 r^{2} = 4

Divide both sides by

49

r^{2} = \frac{4}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{4}{49}, r = - \frac{4}{49}

\frac{4}{49} = \frac{2}{7}

- \frac{4}{49} = - \frac{2}{7}

r = \frac{2}{7}, r = - \frac{2}{7}

\frac{( x + 3 ) ^{2}}{4} = 9

(2 a^{3} b^{- 2}) (- 4 a^{2} b^{4})

x^{2} - 14 x + 113 = 0

- 10 q^{2} + 2600 q - 150000 = 0

4320

What are the solutions to the equation 49r^2-4=0 ?
The solutions to the equation 49r^2-4=0 are r= 2/7 ,r=-2/7
Find the zeros of 49r^2-4=0
The zeros of 49r^2-4=0 are r= 2/7 ,r=-2/7