What are the solutions to the equation 4a^2=8a-4 ?

The solutions to the equation 4a^2=8a-4 are a=1

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4a^2=8a-4

4 a^{2} = 8 a - 4

a = 1

Solution steps

4 a^{2} = 8 a - 4

Move

4

to the left side

4 a^{2} + 4 = 8 a

Move

8 a

to the left side

4 a^{2} + 4 - 8 a = 0

Write in the standard form

a x^{2} + b x + c = 0

4 a^{2} - 8 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 4 = 0

a_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 4}

a = \frac{- ( - 8 )}{2 \cdot 4}

\frac{- ( - 8 )}{2 \cdot 4} = 1

a = 1

The solution to the quadratic equation is:

a = 1

- x^{2} - 10 x + 4 = 0

\frac{c + 2}{4 c} + \frac{2 c - 3}{9 c}

(- 5 z)^{3}

\frac{9}{2} x - \frac{1}{2} = \frac{53}{2}

3 x + 1 = 2 x - 5

What are the solutions to the equation 4a^2=8a-4 ?
The solutions to the equation 4a^2=8a-4 are a=1
Find the zeros of 4a^2=8a-4
The zeros of 4a^2=8a-4 are a=1