What are the solutions to the equation -x^2-10x+4=0 ?

The solutions to the equation -x^2-10x+4=0 are x=-5-sqrt(29),x=sqrt(29)-5

Find the zeros of -x^2-10x+4=0

The zeros of -x^2-10x+4=0 are x=-5-sqrt(29),x=sqrt(29)-5

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- x^{2} - 10 x + 4 = 0

x = - 5 - 29, x = 29 - 5

Decimal Notation

x = - 10.38516 \dots, x = 0.38516 \dots

Solution steps

- x^{2} - 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) \cdot 4 = 229

x_{1, 2} = \frac{- ( - 10 ) \pm 2 29}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 29}{2 ( - 1 )}, x_{2} = \frac{- ( - 10 ) - 2 29}{2 ( - 1 )}

x = \frac{- ( - 10 ) + 2 29}{2 ( - 1 )} : - 5 - 29

x = \frac{- ( - 10 ) - 2 29}{2 ( - 1 )} : 29 - 5

The solutions to the quadratic equation are:

x = - 5 - 29, x = 29 - 5

\frac{c + 2}{4 c} + \frac{2 c - 3}{9 c}

(- 5 z)^{3}

\frac{9}{2} x - \frac{1}{2} = \frac{53}{2}

3 x + 1 = 2 x - 5

2 x^{2} + 28 x = - 79

What are the solutions to the equation -x^2-10x+4=0 ?
The solutions to the equation -x^2-10x+4=0 are x=-5-sqrt(29),x=sqrt(29)-5
Find the zeros of -x^2-10x+4=0
The zeros of -x^2-10x+4=0 are x=-5-sqrt(29),x=sqrt(29)-5