What are the solutions to the equation 2x^2+28x=-79 ?

The solutions to the equation 2x^2+28x=-79 are x=(-14+sqrt(38))/2 ,x=-(14+sqrt(38))/2

Find the zeros of 2x^2+28x=-79

The zeros of 2x^2+28x=-79 are x=(-14+sqrt(38))/2 ,x=-(14+sqrt(38))/2

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2 x^{2} + 28 x = - 79

x = \frac{- 14 + 38}{2}, x = - \frac{14 + 38}{2}

Decimal Notation

x = - 3.91779 \dots, x = - 10.08220 \dots

Solution steps

2 x^{2} + 28 x = - 79

Move

79

to the left side

2 x^{2} + 28 x + 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 2 \cdot 79}{2 \cdot 2}

2 8^{2} - 4 \cdot 2 \cdot 79 = 238

x_{1, 2} = \frac{- 28 \pm 2 38}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 28 + 2 38}{2 \cdot 2}, x_{2} = \frac{- 28 - 2 38}{2 \cdot 2}

x = \frac{- 28 + 2 38}{2 \cdot 2} : \frac{- 14 + 38}{2}

x = \frac{- 28 - 2 38}{2 \cdot 2} : - \frac{14 + 38}{2}

The solutions to the quadratic equation are:

x = \frac{- 14 + 38}{2}, x = - \frac{14 + 38}{2}

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27 y^{2} - 31 y + 4

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What are the solutions to the equation 2x^2+28x=-79 ?
The solutions to the equation 2x^2+28x=-79 are x=(-14+sqrt(38))/2 ,x=-(14+sqrt(38))/2
Find the zeros of 2x^2+28x=-79
The zeros of 2x^2+28x=-79 are x=(-14+sqrt(38))/2 ,x=-(14+sqrt(38))/2