What are the solutions to the equation 3t^2+11t-20=0 ?

The solutions to the equation 3t^2+11t-20=0 are t= 4/3 ,t=-5

Find the zeros of 3t^2+11t-20=0

The zeros of 3t^2+11t-20=0 are t= 4/3 ,t=-5

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3 t^{2} + 11 t - 20 = 0

t = \frac{4}{3}, t = - 5

Decimal Notation

t = 1.33333 \dots, t = - 5

Solution steps

3 t^{2} + 11 t - 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 (- 20) = 19

t_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 11 + 19}{2 \cdot 3}, t_{2} = \frac{- 11 - 19}{2 \cdot 3}

t = \frac{- 11 + 19}{2 \cdot 3} : \frac{4}{3}

t = \frac{- 11 - 19}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

t = \frac{4}{3}, t = - 5

5 x^{3} y - 5 x y

x^{3} + 2 x^{2} + 25 x + 50 x

27 y^{2} - 31 y + 4

x^{2} + 8 x - 84 = 0

0.0 2^{2}

What are the solutions to the equation 3t^2+11t-20=0 ?
The solutions to the equation 3t^2+11t-20=0 are t= 4/3 ,t=-5
Find the zeros of 3t^2+11t-20=0
The zeros of 3t^2+11t-20=0 are t= 4/3 ,t=-5