What are the solutions to the equation 3x^2+36x=-42 ?

The solutions to the equation 3x^2+36x=-42 are x=-6+sqrt(22),x=-6-sqrt(22)

Find the zeros of 3x^2+36x=-42

The zeros of 3x^2+36x=-42 are x=-6+sqrt(22),x=-6-sqrt(22)

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3 x^{2} + 36 x = - 42

x = - 6 + 22, x = - 6 - 22

Decimal Notation

x = - 1.30958 \dots, x = - 10.69041 \dots

Solution steps

3 x^{2} + 36 x = - 42

Move

42

to the left side

3 x^{2} + 36 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 3 \cdot 42}{2 \cdot 3}

3 6^{2} - 4 \cdot 3 \cdot 42 = 622

x_{1, 2} = \frac{- 36 \pm 6 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 36 + 6 22}{2 \cdot 3}, x_{2} = \frac{- 36 - 6 22}{2 \cdot 3}

x = \frac{- 36 + 6 22}{2 \cdot 3} : - 6 + 22

x = \frac{- 36 - 6 22}{2 \cdot 3} : - 6 - 22

The solutions to the quadratic equation are:

x = - 6 + 22, x = - 6 - 22

y \leq 2 and y > - 5

\frac{19 - 4 i}{2 - 5 i} - \frac{3 + 2 i}{i}

\frac{i}{- i}

y^{3} - 125 z^{3}

3 (v + 2) + 2 v = 7 (v - 1) + 9

What are the solutions to the equation 3x^2+36x=-42 ?
The solutions to the equation 3x^2+36x=-42 are x=-6+sqrt(22),x=-6-sqrt(22)
Find the zeros of 3x^2+36x=-42
The zeros of 3x^2+36x=-42 are x=-6+sqrt(22),x=-6-sqrt(22)