What are the solutions to the equation x^2+14x+57=0 ?

The solutions to the equation x^2+14x+57=0 are x=-7+2sqrt(2)i,x=-7-2sqrt(2)i

Find the zeros of x^2+14x+57=0

The zeros of x^2+14x+57=0 are x=-7+2sqrt(2)i,x=-7-2sqrt(2)i

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x^{2} + 14 x + 57 = 0

x = - 7 + 22 i, x = - 7 - 22 i

Solution steps

x^{2} + 14 x + 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 57}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 57 : 42 i

x_{1, 2} = \frac{- 14 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 14 - 4 2 i}{2 \cdot 1}

x = \frac{- 14 + 4 2 i}{2 \cdot 1} : - 7 + 22 i

x = \frac{- 14 - 4 2 i}{2 \cdot 1} : - 7 - 22 i

The solutions to the quadratic equation are:

x = - 7 + 22 i, x = - 7 - 22 i

y, y + ∣ x ∣ - 8 = 0

\frac{x}{2} - \frac{1}{6} \leq \frac{x}{3} + 1

\frac{30 π}{180}

- 2 x^{2} - 5 x + 3 = 0

0 = 4 x^{2} + 12 x + 8

What are the solutions to the equation x^2+14x+57=0 ?
The solutions to the equation x^2+14x+57=0 are x=-7+2sqrt(2)i,x=-7-2sqrt(2)i
Find the zeros of x^2+14x+57=0
The zeros of x^2+14x+57=0 are x=-7+2sqrt(2)i,x=-7-2sqrt(2)i