|2x+1|<7

Solution

∣ 2 x + 1 ∣ < 7

- 4 < x < 3

Interval Notation

(- 4, 3)

Solution steps

∣ 2 x + 1 ∣ < 7

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 7 < 2 x + 1 < 7

2 x + 1 > - 7 and 2 x + 1 < 7

x > - 4 and x < 3

Merge Overlapping Intervals

- 4 < x < 3

\frac{a ^{2} + 11 a + 24}{a ^{3} + 27}

\frac{75 ( 35 )}{85 - 35}

- \frac{19}{2} (\frac{1}{100}) + \frac{19}{2}

\frac{4 x - 1}{5} + \frac{x + 4}{2} = 3

h + 3 \leq 7