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Popular >

2<2x+2<= 8

Solution

2 < 2 x + 2 \leq 8

Solution

0 < x \leq 3

+1

Interval Notation

(0, 3]

Solution steps

2 < 2 x + 2 \leq 8

If

a < u \leq b

then

a < u and u \leq b

2 < 2 x + 2 and 2 x + 2 \leq 8

2 < 2 x + 2 : x > 0

2 x + 2 \leq 8 : x \leq 3

Combine the intervals

x > 0 and x \leq 3

Merge Overlapping Intervals

0 < x \leq 3

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a^{2} - 7 ab + 10 b^{2}

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4 t^{4} + 4 t^{2} + 1

(x^2+6x)/(x-4)>0

\frac{x ^{2} + 6 x}{x - 4} > 0

Frequently Asked Questions (FAQ)

What is 2<2x+2<= 8 ?
The solution to 2<2x+2<= 8 is 0<x<= 3