What are the solutions to the equation 2v^2-7v-4=0 ?

The solutions to the equation 2v^2-7v-4=0 are v=4,v=-1/2

Find the zeros of 2v^2-7v-4=0

The zeros of 2v^2-7v-4=0 are v=4,v=-1/2

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2 v^{2} - 7 v - 4 = 0

v = 4, v = - \frac{1}{2}

Decimal Notation

v = 4, v = - 0.5

Solution steps

2 v^{2} - 7 v - 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 4) = 9

v_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 2}, v_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 2}

v = \frac{- ( - 7 ) + 9}{2 \cdot 2} : 4

v = \frac{- ( - 7 ) - 9}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

v = 4, v = - \frac{1}{2}

- 5 g + 2.3 = - 18.8

(x + 9)^{2} = 0

6 x + 8 = - 62 - 4 x

2 \cdot (x - \frac{1}{5}) - 4 x - 1 = \frac{x}{3}

(\frac{5 x}{y})^{2} (\frac{y ^{3}}{10 x ^{2}})

What are the solutions to the equation 2v^2-7v-4=0 ?
The solutions to the equation 2v^2-7v-4=0 are v=4,v=-1/2
Find the zeros of 2v^2-7v-4=0
The zeros of 2v^2-7v-4=0 are v=4,v=-1/2