What are the solutions to the equation c^2-16=0 ?

The solutions to the equation c^2-16=0 are c=4,c=-4

Find the zeros of c^2-16=0

The zeros of c^2-16=0 are c=4,c=-4

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c^{2} - 16 = 0

c = 4, c = - 4

Solution steps

c^{2} - 16 = 0

Move

16

to the right side

c^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 16, c = - 16

16 = 4

- 16 = - 4

c = 4, c = - 4

\frac{4 x - 6}{( x + 9 ) ( x + 1 )} \geq 0

2 x^{2} = 27 - x^{2}

\frac{1}{8} x^{2} - x - 16 = 0

w + 5 < 8

6 p^{2} + p - 4 = 0

What are the solutions to the equation c^2-16=0 ?
The solutions to the equation c^2-16=0 are c=4,c=-4
Find the zeros of c^2-16=0
The zeros of c^2-16=0 are c=4,c=-4