What are the solutions to the equation x^2+4x=45 ?

The solutions to the equation x^2+4x=45 are x=5,x=-9

Find the zeros of x^2+4x=45

The zeros of x^2+4x=45 are x=5,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 x = 45

x = 5, x = - 9

Solution steps

x^{2} + 4 x = 45

Move

45

to the left side

x^{2} + 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 14}{2 \cdot 1}

x = \frac{- 4 + 14}{2 \cdot 1} : 5

x = \frac{- 4 - 14}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

x^{2} + 12 x = 9

(- 1)^{- 2}

d^{2} + 8 d + 15

- 40 m - 30

ln (a + b) + ln (a - b) - 2 ln (c)

What are the solutions to the equation x^2+4x=45 ?
The solutions to the equation x^2+4x=45 are x=5,x=-9
Find the zeros of x^2+4x=45
The zeros of x^2+4x=45 are x=5,x=-9