What are the solutions to the equation 2x^2-11x=87 ?

The solutions to the equation 2x^2-11x=87 are x=(11+sqrt(817))/4 ,x=(11-sqrt(817))/4

Find the zeros of 2x^2-11x=87

The zeros of 2x^2-11x=87 are x=(11+sqrt(817))/4 ,x=(11-sqrt(817))/4

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2 x^{2} - 11 x = 87

x = \frac{11 + 817}{4}, x = \frac{11 - 817}{4}

Decimal Notation

x = 9.89580 \dots, x = - 4.39580 \dots

Solution steps

2 x^{2} - 11 x = 87

Move

87

to the left side

2 x^{2} - 11 x - 87 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 87 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 87) = 817

x_{1, 2} = \frac{- ( - 11 ) \pm 817}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 817}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 817}{2 \cdot 2}

x = \frac{- ( - 11 ) + 817}{2 \cdot 2} : \frac{11 + 817}{4}

x = \frac{- ( - 11 ) - 817}{2 \cdot 2} : \frac{11 - 817}{4}

The solutions to the quadratic equation are:

x = \frac{11 + 817}{4}, x = \frac{11 - 817}{4}

3 (2 + x) = 4 - (x - 2)

(- 2 x^{2} y^{5})^{3}

- 4 x + 40 < 4 x + 8

\frac{m}{4} = - 13

\frac{3 ^{7} \cdot 3 ^{- 4} \cdot 2 ^{2}}{3 ^{4} \cdot 2 ^{- 2} \cdot 4 ^{2}}

What are the solutions to the equation 2x^2-11x=87 ?
The solutions to the equation 2x^2-11x=87 are x=(11+sqrt(817))/4 ,x=(11-sqrt(817))/4
Find the zeros of 2x^2-11x=87
The zeros of 2x^2-11x=87 are x=(11+sqrt(817))/4 ,x=(11-sqrt(817))/4