What are the solutions to the equation (x-1)(x+5)=40 ?

The solutions to the equation (x-1)(x+5)=40 are x=5,x=-9

Find the zeros of (x-1)(x+5)=40

The zeros of (x-1)(x+5)=40 are x=5,x=-9

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(x - 1) (x + 5) = 40

x = 5, x = - 9

Solution steps

(x - 1) (x + 5) = 40

Expand

(x - 1) (x + 5) : x^{2} + 4 x - 5

x^{2} + 4 x - 5 = 40

Move

40

to the left side

x^{2} + 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 14}{2 \cdot 1}

x = \frac{- 4 + 14}{2 \cdot 1} : 5

x = \frac{- 4 - 14}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

2 (- \frac{3}{2})^{2}

12 x^{2} + 12 x + 3

\frac{x - 6}{x + 4} \leq 0

0. 7^{3}

(7 - i (2 \cdot 3 - 1)) w = (6 - i (3 \cdot 2 + 2)) w - i

What are the solutions to the equation (x-1)(x+5)=40 ?
The solutions to the equation (x-1)(x+5)=40 are x=5,x=-9
Find the zeros of (x-1)(x+5)=40
The zeros of (x-1)(x+5)=40 are x=5,x=-9