What are the solutions to the equation 2x^2-1x-15=0 ?

The solutions to the equation 2x^2-1x-15=0 are x=3,x=-5/2

Find the zeros of 2x^2-1x-15=0

The zeros of 2x^2-1x-15=0 are x=3,x=-5/2

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2 x^{2} - 1 x - 15 = 0

x = 3, x = - \frac{5}{2}

Solution steps

2 x^{2} - 1 \cdot x - 15 = 0

Refine

2 x^{2} - x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 2}

x = \frac{- ( - 1 ) + 11}{2 \cdot 2} : 3

x = \frac{- ( - 1 ) - 11}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{5}{2}

\frac{3}{10} \cdot 4

4 v^{2} + 28 v = 0

3 x^{2} + 3 x

\frac{1}{a b ^{2}} + \frac{1}{a ^{2} b}

\frac{8 x ^{- 3} y \cdot 5 x ^{5} y}{10 x ^{6} y ^{2}}

What are the solutions to the equation 2x^2-1x-15=0 ?
The solutions to the equation 2x^2-1x-15=0 are x=3,x=-5/2
Find the zeros of 2x^2-1x-15=0
The zeros of 2x^2-1x-15=0 are x=3,x=-5/2