What is 1/(ab^2)+1/(a^2b) ?

The solution to 1/(ab^2)+1/(a^2b) is (a+b)/(a^2b^2)

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simplify 1/(ab^2)+1/(a^2b)

simplify

\frac{1}{a b ^{2}} + \frac{1}{a ^{2} b}

\frac{a + b}{a ^{2} b ^{2}}

Solution steps

\frac{1}{a b ^{2}} + \frac{1}{a ^{2} b}

Least Common Multiplier of

a b^{2}, a^{2} b : a^{2} b^{2}

Adjust Fractions based on the LCM

= \frac{a}{a ^{2} b ^{2}} + \frac{b}{a ^{2} b ^{2}}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{a + b}{a ^{2} b ^{2}}

\frac{8 x ^{- 3} y \cdot 5 x ^{5} y}{10 x ^{6} y ^{2}}

b^{2} - 12 b + 36

p^{2} + 4 p = 1

[2 v - 6] = [2 v + 4]

(m + 2) 2 - (m + 2) + mn \cdot (n + 2) + 2 n (n + 2)