What are the solutions to the equation 3d^2-11d+8=6 ?

The solutions to the equation 3d^2-11d+8=6 are d=(11+sqrt(97))/6 ,d=(11-sqrt(97))/6

Find the zeros of 3d^2-11d+8=6

The zeros of 3d^2-11d+8=6 are d=(11+sqrt(97))/6 ,d=(11-sqrt(97))/6

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3 d^{2} - 11 d + 8 = 6

d = \frac{11 + 97}{6}, d = \frac{11 - 97}{6}

Decimal Notation

d = 3.47480 \dots, d = 0.19185 \dots

Solution steps

3 d^{2} - 11 d + 8 = 6

Move

6

to the left side

3 d^{2} - 11 d + 2 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 \cdot 2 = 97

d_{1, 2} = \frac{- ( - 11 ) \pm 97}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- ( - 11 ) + 97}{2 \cdot 3}, d_{2} = \frac{- ( - 11 ) - 97}{2 \cdot 3}

d = \frac{- ( - 11 ) + 97}{2 \cdot 3} : \frac{11 + 97}{6}

d = \frac{- ( - 11 ) - 97}{2 \cdot 3} : \frac{11 - 97}{6}

The solutions to the quadratic equation are:

d = \frac{11 + 97}{6}, d = \frac{11 - 97}{6}

x^{2} + 3 x - 3 = 0

- \frac{9}{6} + (- \frac{3}{5})

(x^{2} + x + 3) (x^{2} + x + 4) - 12

\frac{\frac{4}{5}}{6}

6 \cdot 4

What are the solutions to the equation 3d^2-11d+8=6 ?
The solutions to the equation 3d^2-11d+8=6 are d=(11+sqrt(97))/6 ,d=(11-sqrt(97))/6
Find the zeros of 3d^2-11d+8=6
The zeros of 3d^2-11d+8=6 are d=(11+sqrt(97))/6 ,d=(11-sqrt(97))/6