What are the solutions to the equation x^2+9x-36=0 ?

The solutions to the equation x^2+9x-36=0 are x=3,x=-12

Find the zeros of x^2+9x-36=0

The zeros of x^2+9x-36=0 are x=3,x=-12

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x^{2} + 9 x - 36 = 0

x = 3, x = - 12

Solution steps

x^{2} + 9 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 36) = 15

x_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 15}{2 \cdot 1}, x_{2} = \frac{- 9 - 15}{2 \cdot 1}

x = \frac{- 9 + 15}{2 \cdot 1} : 3

x = \frac{- 9 - 15}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 3, x = - 12

w^{2} (w + 8) - 5 (w + 8)

r^{2} - 8 r + 17 = 0

32 - \frac{64}{3}

- - 54

x^{2} + 14 x y + 33 y^{2}

What are the solutions to the equation x^2+9x-36=0 ?
The solutions to the equation x^2+9x-36=0 are x=3,x=-12
Find the zeros of x^2+9x-36=0
The zeros of x^2+9x-36=0 are x=3,x=-12