What are the solutions to the equation 2a^2+18=0 ?

The solutions to the equation 2a^2+18=0 are a=3i,a=-3i

Find the zeros of 2a^2+18=0

The zeros of 2a^2+18=0 are a=3i,a=-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 a^{2} + 18 = 0

a = 3 i, a = - 3 i

Solution steps

2 a^{2} + 18 = 0

Move

18

to the right side

2 a^{2} = - 18

Divide both sides by

2

a^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - 9, a = - - 9

- 9 = 3 i

- - 9 = - 3 i

a = 3 i, a = - 3 i

\frac{1}{4} x^{2} - \frac{1}{2} x = 1

25 x^{2} + 20 x = 6

5 x^{2} - 14 x - 3

(12 + 4 i) - (3 - 7 i)

(3 + 5) (3 - 5)

What are the solutions to the equation 2a^2+18=0 ?
The solutions to the equation 2a^2+18=0 are a=3i,a=-3i
Find the zeros of 2a^2+18=0
The zeros of 2a^2+18=0 are a=3i,a=-3i