What are the solutions to the equation (2x-3)^2=81 ?

The solutions to the equation (2x-3)^2=81 are x=6,x=-3

Find the zeros of (2x-3)^2=81

The zeros of (2x-3)^2=81 are x=6,x=-3

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(2 x - 3)^{2} = 81

x = 6, x = - 3

Solution steps

(2 x - 3)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 81 : x = 6

Solve

2 x - 3 = - 81 : x = - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

27 x^{3} + 1

- 1 \leq x < 2

x^{2} - 30 x + 150 \leq 0

2 x^{2} - 3 = 253

C a (s) + M g C l^{2} (a p)

What are the solutions to the equation (2x-3)^2=81 ?
The solutions to the equation (2x-3)^2=81 are x=6,x=-3
Find the zeros of (2x-3)^2=81
The zeros of (2x-3)^2=81 are x=6,x=-3