What are the solutions to the equation x(7x-5)=12 ?

The solutions to the equation x(7x-5)=12 are x= 12/7 ,x=-1

Find the zeros of x(7x-5)=12

The zeros of x(7x-5)=12 are x= 12/7 ,x=-1

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x (7 x - 5) = 12

x = \frac{12}{7}, x = - 1

Solution steps

x (7 x - 5) = 12

Expand

x (7 x - 5) : 7 x^{2} - 5 x

7 x^{2} - 5 x = 12

Move

12

to the left side

7 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 ( - 12 )}{2 \cdot 7}

(- 5)^{2} - 4 \cdot 7 (- 12) = 19

x_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 7}, x_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 7}

x = \frac{- ( - 5 ) + 19}{2 \cdot 7} : \frac{12}{7}

x = \frac{- ( - 5 ) - 19}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{12}{7}, x = - 1

6 x^{2} - 9 x + 2 = 0

4 (6 x - 10) = 8 x + 40

\frac{1}{2} x + 5 = \frac{3}{10} x

(x - 2)^{2} = 25

\frac{2}{x - 4} \geq \frac{- 6}{5 - x}

What are the solutions to the equation x(7x-5)=12 ?
The solutions to the equation x(7x-5)=12 are x= 12/7 ,x=-1
Find the zeros of x(7x-5)=12
The zeros of x(7x-5)=12 are x= 12/7 ,x=-1