What are the solutions to the equation 2(x+4)^2=6 ?

The solutions to the equation 2(x+4)^2=6 are x=sqrt(3)-4,x=-sqrt(3)-4

Find the zeros of 2(x+4)^2=6

The zeros of 2(x+4)^2=6 are x=sqrt(3)-4,x=-sqrt(3)-4

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2 (x + 4)^{2} = 6

x = 3 - 4, x = - 3 - 4

Decimal Notation

x = - 2.26794 \dots, x = - 5.73205 \dots

Solution steps

2 (x + 4)^{2} = 6

Divide both sides by

2

(x + 4)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 3 : x = 3 - 4

Solve

x + 4 = - 3 : x = - 3 - 4

The solutions to the quadratic equation are:

x = 3 - 4, x = - 3 - 4

\frac{3}{2} s = 2

x^{4} - 34 x^{2} - 72 < 0

324

3 n - 4 (n - 2) < 3 n - 12

(4 a^{2} b) (3 b^{2} - a + \frac{b}{2 a ^{2}})

What are the solutions to the equation 2(x+4)^2=6 ?
The solutions to the equation 2(x+4)^2=6 are x=sqrt(3)-4,x=-sqrt(3)-4
Find the zeros of 2(x+4)^2=6
The zeros of 2(x+4)^2=6 are x=sqrt(3)-4,x=-sqrt(3)-4