What is the answer to (x-4)(x+6)-(x-3)^2=15 ?

The answer to (x-4)(x+6)-(x-3)^2=15 is x=6

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(x-4)(x+6)-(x-3)^2=15

(x - 4) (x + 6) - (x - 3)^{2} = 15

x = 6

Solution steps

(x - 4) (x + 6) - (x - 3)^{2} = 15

Expand

(x - 4) (x + 6) - (x - 3)^{2} : 8 x - 33

8 x - 33 = 15

Move

33

to the right side

8 x = 48

Divide both sides by

8

x = 6

9^{2} + 4 0^{2}

∣ 3 a + 4 ∣ = ∣ 4 a - 10 ∣

x^{3} y^{3} + 343

\frac{3 + 5 x}{5} = \frac{4 - x}{8}

3 (x - 2)^{2} = 40

What is the answer to (x-4)(x+6)-(x-3)^2=15 ?
The answer to (x-4)(x+6)-(x-3)^2=15 is x=6
Solve for x: (x-4)(x+6)-(x-3)^2=15
The solution is x=6