What are the solutions to the equation 3(x+1)^2-(2x+1)^2=2x-14 ?

The solutions to the equation 3(x+1)^2-(2x+1)^2=2x-14 are x=4,x=-4

Find the zeros of 3(x+1)^2-(2x+1)^2=2x-14

The zeros of 3(x+1)^2-(2x+1)^2=2x-14 are x=4,x=-4

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3 (x + 1)^{2} - (2 x + 1)^{2} = 2 x - 14

x = 4, x = - 4

Solution steps

3 (x + 1)^{2} - (2 x + 1)^{2} = 2 x - 14

Expand

3 (x + 1)^{2} - (2 x + 1)^{2} : - x^{2} + 2 x + 2

- x^{2} + 2 x + 2 = 2 x - 14

Move

2

to the right side

- x^{2} + 2 x = 2 x - 16

Move

2 x

to the left side

- x^{2} = - 16

Divide both sides by

- 1

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x^{3} + \frac{- 3}{4 ^{\frac{1}{3}}} B^{\frac{2}{3}} x + B

64 - 40 ab

1 + \frac{1}{2}

\frac{\frac{3}{w} + \frac{2}{x}}{\frac{2}{w} - \frac{3}{x}}

y^{2} + 7 = 6 y

What are the solutions to the equation 3(x+1)^2-(2x+1)^2=2x-14 ?
The solutions to the equation 3(x+1)^2-(2x+1)^2=2x-14 are x=4,x=-4
Find the zeros of 3(x+1)^2-(2x+1)^2=2x-14
The zeros of 3(x+1)^2-(2x+1)^2=2x-14 are x=4,x=-4