What are the solutions to the equation x^2+9x+4=-x+4 ?

The solutions to the equation x^2+9x+4=-x+4 are x=0,x=-10

Find the zeros of x^2+9x+4=-x+4

The zeros of x^2+9x+4=-x+4 are x=0,x=-10

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x^{2} + 9 x + 4 = - x + 4

x = 0, x = - 10

Solution steps

x^{2} + 9 x + 4 = - x + 4

Move

4

to the left side

x^{2} + 9 x = - x

Move

x

to the left side

x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 \cdot 1}, x_{2} = \frac{- 10 - 10}{2 \cdot 1}

x = \frac{- 10 + 10}{2 \cdot 1} : 0

x = \frac{- 10 - 10}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 0, x = - 10

4 x^{3} (4 x - 8)^{2} + x^{4} (2) (4 x - 8) (8)

5 x^{3} + 25 x^{2} + 30 x

a^{2} + 6 a + 9 - b^{2}

2 x^{2} + 4 x - 9 = 0

5 x - 1 (8 - x) = 10

What are the solutions to the equation x^2+9x+4=-x+4 ?
The solutions to the equation x^2+9x+4=-x+4 are x=0,x=-10
Find the zeros of x^2+9x+4=-x+4
The zeros of x^2+9x+4=-x+4 are x=0,x=-10