What are the solutions to the equation 3x^2+7x-6=0 ?

The solutions to the equation 3x^2+7x-6=0 are x= 2/3 ,x=-3

Find the zeros of 3x^2+7x-6=0

The zeros of 3x^2+7x-6=0 are x= 2/3 ,x=-3

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3 x^{2} + 7 x - 6 = 0

x = \frac{2}{3}, x = - 3

Solution steps

3 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 3}, x_{2} = \frac{- 7 - 11}{2 \cdot 3}

x = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 3

360 \cdot \frac{π}{180}

4 x^{2} + 5 x - 6 = 0

(- 25)^{2}

n (1 - \frac{t}{1 - x})^{n - 1} \cdot \frac{1}{1 - x}

2 x^{2} + 6 x + 8 = 0

What are the solutions to the equation 3x^2+7x-6=0 ?
The solutions to the equation 3x^2+7x-6=0 are x= 2/3 ,x=-3
Find the zeros of 3x^2+7x-6=0
The zeros of 3x^2+7x-6=0 are x= 2/3 ,x=-3