What are the solutions to the equation y^2-14y=-42 ?

The solutions to the equation y^2-14y=-42 are y=7+sqrt(7),y=7-sqrt(7)

Find the zeros of y^2-14y=-42

The zeros of y^2-14y=-42 are y=7+sqrt(7),y=7-sqrt(7)

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y^{2} - 14 y = - 42

y = 7 + 7, y = 7 - 7

Solution steps

y^{2} - 14 y = - 42

Move

42

to the left side

y^{2} - 14 y + 42 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 42 = 27

y_{1, 2} = \frac{- ( - 14 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 7}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 2 7}{2 \cdot 1}

y = \frac{- ( - 14 ) + 2 7}{2 \cdot 1} : 7 + 7

y = \frac{- ( - 14 ) - 2 7}{2 \cdot 1} : 7 - 7

The solutions to the quadratic equation are:

y = 7 + 7, y = 7 - 7

\frac{1}{2} x + 2 = x - \frac{1}{4}

- x^{2} + 7 x - 10 = 0

2 (1 - x)^{3} - 3 x (1 - x)^{2}

\frac{16}{n ^{- 3}}

(4 x + 1)^{2} = 12

What are the solutions to the equation y^2-14y=-42 ?
The solutions to the equation y^2-14y=-42 are y=7+sqrt(7),y=7-sqrt(7)
Find the zeros of y^2-14y=-42
The zeros of y^2-14y=-42 are y=7+sqrt(7),y=7-sqrt(7)