What are the solutions to the equation 4x^2-2=47 ?

The solutions to the equation 4x^2-2=47 are x= 7/2 ,x=-7/2

Find the zeros of 4x^2-2=47

The zeros of 4x^2-2=47 are x= 7/2 ,x=-7/2

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4 x^{2} - 2 = 47

x = \frac{7}{2}, x = - \frac{7}{2}

Solution steps

4 x^{2} - 2 = 47

Move

2

to the right side

4 x^{2} = 49

Divide both sides by

4

x^{2} = \frac{49}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{4}, x = - \frac{49}{4}

\frac{49}{4} = \frac{7}{2}

- \frac{49}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

x^{2} - 6 x + 6 \leq 0

x = 1 - x^{2}

2 w^{3} - 8 w^{2} - 90 w

- 6 r + 3 = - 39

(\frac{m ^{- 1} m ^{5}}{m ^{- 2}})^{- 3}

What are the solutions to the equation 4x^2-2=47 ?
The solutions to the equation 4x^2-2=47 are x= 7/2 ,x=-7/2
Find the zeros of 4x^2-2=47
The zeros of 4x^2-2=47 are x= 7/2 ,x=-7/2