What are the solutions to the equation x(x+1)=72 ?

The solutions to the equation x(x+1)=72 are x=8,x=-9

Find the zeros of x(x+1)=72

The zeros of x(x+1)=72 are x=8,x=-9

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x (x + 1) = 72

x = 8, x = - 9

Solution steps

x (x + 1) = 72

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 72

Move

72

to the left side

x^{2} + x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 72) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 1}, x_{2} = \frac{- 1 - 17}{2 \cdot 1}

x = \frac{- 1 + 17}{2 \cdot 1} : 8

x = \frac{- 1 - 17}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 8, x = - 9

\frac{k - 3}{4} = 10

\frac{8 x + 1}{3 x - 1} \leq 4

- 67 = 6 x - 1

\frac{15. 2 ^{2}}{2 \cdot 9.8}

n^{2} - 7 n - 8 = 0

What are the solutions to the equation x(x+1)=72 ?
The solutions to the equation x(x+1)=72 are x=8,x=-9
Find the zeros of x(x+1)=72
The zeros of x(x+1)=72 are x=8,x=-9