What are the solutions to the equation n^2-7n-8=0 ?

The solutions to the equation n^2-7n-8=0 are n=8,n=-1

Find the zeros of n^2-7n-8=0

The zeros of n^2-7n-8=0 are n=8,n=-1

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n^{2} - 7 n - 8 = 0

n = 8, n = - 1

Solution steps

n^{2} - 7 n - 8 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

n_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, n_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

n = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

n = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 8, n = - 1

9 (z + 1)^{2} + 12 = 16

2 (3 x - 7) = 16

8 \div 2 (1 + 3)

0 = 4 x^{2} + 3 x + 8

- 2 x > - 3

What are the solutions to the equation n^2-7n-8=0 ?
The solutions to the equation n^2-7n-8=0 are n=8,n=-1
Find the zeros of n^2-7n-8=0
The zeros of n^2-7n-8=0 are n=8,n=-1