What are the solutions to the equation 5x^2-2x-5=0 ?

The solutions to the equation 5x^2-2x-5=0 are x=(1+sqrt(26))/5 ,x=(1-sqrt(26))/5

Find the zeros of 5x^2-2x-5=0

The zeros of 5x^2-2x-5=0 are x=(1+sqrt(26))/5 ,x=(1-sqrt(26))/5

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5 x^{2} - 2 x - 5 = 0

x = \frac{1 + 26}{5}, x = \frac{1 - 26}{5}

Decimal Notation

x = 1.21980 \dots, x = - 0.81980 \dots

Solution steps

5 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 5) = 226

x_{1, 2} = \frac{- ( - 2 ) \pm 2 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 26}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 2 26}{2 \cdot 5}

x = \frac{- ( - 2 ) + 2 26}{2 \cdot 5} : \frac{1 + 26}{5}

x = \frac{- ( - 2 ) - 2 26}{2 \cdot 5} : \frac{1 - 26}{5}

The solutions to the quadratic equation are:

x = \frac{1 + 26}{5}, x = \frac{1 - 26}{5}

7 x - 3 \leq 25

- 5 x^{2} + 120 x - 400 = 0

x + 1 = - x - 1

(x + 2)^{2} = 14

x^{4} + \frac{5}{3} x^{3} + \frac{10}{3} x^{2} + \frac{20}{3} x - \frac{8}{3}

What are the solutions to the equation 5x^2-2x-5=0 ?
The solutions to the equation 5x^2-2x-5=0 are x=(1+sqrt(26))/5 ,x=(1-sqrt(26))/5
Find the zeros of 5x^2-2x-5=0
The zeros of 5x^2-2x-5=0 are x=(1+sqrt(26))/5 ,x=(1-sqrt(26))/5