What are the solutions to the equation -5x^2+120x-400=0 ?

The solutions to the equation -5x^2+120x-400=0 are x=4,x=20

Find the zeros of -5x^2+120x-400=0

The zeros of -5x^2+120x-400=0 are x=4,x=20

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- 5 x^{2} + 120 x - 400 = 0

x = 4, x = 20

Solution steps

- 5 x^{2} + 120 x - 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 ( - 5 ) ( - 400 )}{2 ( - 5 )}

12 0^{2} - 4 (- 5) (- 400) = 80

x_{1, 2} = \frac{- 120 \pm 80}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 120 + 80}{2 ( - 5 )}, x_{2} = \frac{- 120 - 80}{2 ( - 5 )}

x = \frac{- 120 + 80}{2 ( - 5 )} : 4

x = \frac{- 120 - 80}{2 ( - 5 )} : 20

The solutions to the quadratic equation are:

x = 4, x = 20

x + 1 = - x - 1

(x + 2)^{2} = 14

x^{4} + \frac{5}{3} x^{3} + \frac{10}{3} x^{2} + \frac{20}{3} x - \frac{8}{3}

r = (0)^{2} + (- 3)^{2}

4.4 = - 0.5 x^{2} + 1.15 x + 4.3

What are the solutions to the equation -5x^2+120x-400=0 ?
The solutions to the equation -5x^2+120x-400=0 are x=4,x=20
Find the zeros of -5x^2+120x-400=0
The zeros of -5x^2+120x-400=0 are x=4,x=20