What is |5x-7|<= 3x+6 ?

The solution to |5x-7|<= 3x+6 is 1/8 <= x<= 13/2

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|5x-7|<= 3x+6

∣ 5 x - 7 ∣ \leq 3 x + 6

\frac{1}{8} \leq x \leq \frac{13}{2}

Interval Notation

[\frac{1}{8}, \frac{13}{2}]

Decimal Notation

0.125 \leq x \leq 6.5

Solution steps

∣ 5 x - 7 ∣ \leq 3 x + 6

Find positive and negative intervals

x < \frac{7}{5}, x \geq \frac{7}{5}

Solve the inequality for each interval

\frac{1}{8} \leq x < \frac{7}{5} or \frac{7}{5} \leq x \leq \frac{13}{2}

Merge Overlapping Intervals

\frac{1}{8} \leq x \leq \frac{13}{2}

0 = 1 \cdot 1 + b

8 m - 4 (- 2 m - 2) \leq - 7 m + 3 - 8 m

9 y^{3} + 18 y^{2} + y + 2

x^{2} - 6 x - 40 = 0

(\frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}})^{- \frac{1}{3}}