What are the solutions to the equation y^2-6y+9=0 ?

The solutions to the equation y^2-6y+9=0 are y=3

Find the zeros of y^2-6y+9=0

The zeros of y^2-6y+9=0 are y=3

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y^{2} - 6 y + 9 = 0

y = 3

Solution steps

y^{2} - 6 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

y_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

y = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

y = 3

The solution to the quadratic equation is:

y = 3

k^{2} - 8 k = 0

18 x^{2} - 85 x + 18

(- 3 x^{2})^{2}

- 6 = 3 w^{2} - 11 w

9 + \frac{8 ^{3}}{2}

What are the solutions to the equation y^2-6y+9=0 ?
The solutions to the equation y^2-6y+9=0 are y=3
Find the zeros of y^2-6y+9=0
The zeros of y^2-6y+9=0 are y=3