What is 2x^2+9x+5<= 2-2x-4x^2 ?

The solution to 2x^2+9x+5<= 2-2x-4x^2 is -3/2 <= x<=-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+9x+5<= 2-2x-4x^2

2 x^{2} + 9 x + 5 \leq 2 - 2 x - 4 x^{2}

- \frac{3}{2} \leq x \leq - \frac{1}{3}

Interval Notation

[- \frac{3}{2}, - \frac{1}{3}]

Decimal Notation

- 1.5 \leq x \leq - 0.33333 \dots

Solution steps

2 x^{2} + 9 x + 5 \leq 2 - 2 x - 4 x^{2}

Rewrite in standard form

6 x^{2} + 11 x + 3 \leq 0

Factor

6 x^{2} + 11 x + 3 : (3 x + 1) (2 x + 3)

(3 x + 1) (2 x + 3) \leq 0

Identify the intervals

- \frac{3}{2} \leq x \leq - \frac{1}{3}

\frac{( 2 x + 1 ) ^{2} ( 2 x - 1 ) ^{3}}{( x - 1 ) ^{4}} > 0

\frac{x ^{2}}{y ^{2}}

5 x^{2} - 7 x - 90 = 0

3 x^{2} - 25 x - 18

\frac{4}{11} n = \frac{16}{55}

What is 2x^2+9x+5<= 2-2x-4x^2 ?
The solution to 2x^2+9x+5<= 2-2x-4x^2 is -3/2 <= x<=-1/3