What are the solutions to the equation (a+5)^2=1 ?

The solutions to the equation (a+5)^2=1 are a=-4,a=-6

Find the zeros of (a+5)^2=1

The zeros of (a+5)^2=1 are a=-4,a=-6

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(a + 5)^{2} = 1

a = - 4, a = - 6

Solution steps

(a + 5)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a + 5 = 1 : a = - 4

Solve

a + 5 = - 1 : a = - 6

The solutions to the quadratic equation are:

a = - 4, a = - 6

x + \frac{3}{4} < 5

- 83 = \frac{b}{4}

3 x^{2} + 243 = 0

- 3 x^{2} + 6 x = - 2

10 x - 4 < - 84

What are the solutions to the equation (a+5)^2=1 ?
The solutions to the equation (a+5)^2=1 are a=-4,a=-6
Find the zeros of (a+5)^2=1
The zeros of (a+5)^2=1 are a=-4,a=-6