What are the solutions to the equation -3x^2+6x=-2 ?

The solutions to the equation -3x^2+6x=-2 are x=-(-3+sqrt(15))/3 ,x=(3+sqrt(15))/3

Find the zeros of -3x^2+6x=-2

The zeros of -3x^2+6x=-2 are x=-(-3+sqrt(15))/3 ,x=(3+sqrt(15))/3

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- 3 x^{2} + 6 x = - 2

x = - \frac{- 3 + 15}{3}, x = \frac{3 + 15}{3}

Decimal Notation

x = - 0.29099 \dots, x = 2.29099 \dots

Solution steps

- 3 x^{2} + 6 x = - 2

Move

2

to the left side

- 3 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 2 = 215

x_{1, 2} = \frac{- 6 \pm 2 15}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 15}{2 ( - 3 )}, x_{2} = \frac{- 6 - 2 15}{2 ( - 3 )}

x = \frac{- 6 + 2 15}{2 ( - 3 )} : - \frac{- 3 + 15}{3}

x = \frac{- 6 - 2 15}{2 ( - 3 )} : \frac{3 + 15}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 15}{3}, x = \frac{3 + 15}{3}

10 x - 4 < - 84

3 \cdot 3^{- 1}

\frac{3 x + 3}{7 x + 14}

10 (x - 7)^{2} = 440

∣ x ∣ < 13

What are the solutions to the equation -3x^2+6x=-2 ?
The solutions to the equation -3x^2+6x=-2 are x=-(-3+sqrt(15))/3 ,x=(3+sqrt(15))/3
Find the zeros of -3x^2+6x=-2
The zeros of -3x^2+6x=-2 are x=-(-3+sqrt(15))/3 ,x=(3+sqrt(15))/3