What are the solutions to the equation 6x^2-7x-4=0 ?

The solutions to the equation 6x^2-7x-4=0 are x=(7+sqrt(145))/(12),x=(7-sqrt(145))/(12)

Find the zeros of 6x^2-7x-4=0

The zeros of 6x^2-7x-4=0 are x=(7+sqrt(145))/(12),x=(7-sqrt(145))/(12)

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6 x^{2} - 7 x - 4 = 0

x = \frac{7 + 145}{12}, x = \frac{7 - 145}{12}

Decimal Notation

x = 1.58679 \dots, x = - 0.42013 \dots

Solution steps

6 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 4) = 145

x_{1, 2} = \frac{- ( - 7 ) \pm 145}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 145}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 145}{2 \cdot 6}

x = \frac{- ( - 7 ) + 145}{2 \cdot 6} : \frac{7 + 145}{12}

x = \frac{- ( - 7 ) - 145}{2 \cdot 6} : \frac{7 - 145}{12}

The solutions to the quadratic equation are:

x = \frac{7 + 145}{12}, x = \frac{7 - 145}{12}

6 v^{2} - 24 v = 0

12 = 4 x - 4

6 c^{2} + 7 c + 2

∣ 1 - 2 x ∣ \geq 3

4 (x - 9) + 52 = 2 (3 x + 17) + 2 x

What are the solutions to the equation 6x^2-7x-4=0 ?
The solutions to the equation 6x^2-7x-4=0 are x=(7+sqrt(145))/(12),x=(7-sqrt(145))/(12)
Find the zeros of 6x^2-7x-4=0
The zeros of 6x^2-7x-4=0 are x=(7+sqrt(145))/(12),x=(7-sqrt(145))/(12)