What are the solutions to the equation 3x^2+24x+57=9 ?

The solutions to the equation 3x^2+24x+57=9 are x=-4

Find the zeros of 3x^2+24x+57=9

The zeros of 3x^2+24x+57=9 are x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 24 x + 57 = 9

x = - 4

Solution steps

3 x^{2} + 24 x + 57 = 9

Move

9

to the left side

3 x^{2} + 24 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 48}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 48 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 3}

x = \frac{- 24}{2 \cdot 3}

\frac{- 24}{2 \cdot 3} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

2 x^{2} - 0.45 x - 3 = 0

15 c \cdot (a + b) + 8 \cdot (b + a)

- 5 x^{3} + 6 x^{2} + 15 x - 18

x^{4} - x^{2} - 2 x - 1

∣ 6 - 3 x ∣ \leq 18

What are the solutions to the equation 3x^2+24x+57=9 ?
The solutions to the equation 3x^2+24x+57=9 are x=-4
Find the zeros of 3x^2+24x+57=9
The zeros of 3x^2+24x+57=9 are x=-4