What are the solutions to the equation 3m^2-3m-64=-4 ?

The solutions to the equation 3m^2-3m-64=-4 are m=5,m=-4

Find the zeros of 3m^2-3m-64=-4

The zeros of 3m^2-3m-64=-4 are m=5,m=-4

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3 m^{2} - 3 m - 64 = - 4

m = 5, m = - 4

Solution steps

3 m^{2} - 3 m - 64 = - 4

Move

4

to the left side

3 m^{2} - 3 m - 60 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 60 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 60) = 27

m_{1, 2} = \frac{- ( - 3 ) \pm 27}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 27}{2 \cdot 3}, m_{2} = \frac{- ( - 3 ) - 27}{2 \cdot 3}

m = \frac{- ( - 3 ) + 27}{2 \cdot 3} : 5

m = \frac{- ( - 3 ) - 27}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

m = 5, m = - 4

9 c^{2} + 12 c + 4

- \frac{5 z}{7} = 20

3.6 g = 2.16

16 (9 - 3 x)^{2} + 13 = 49

x^{2} + 5 = 3 x + 5

What are the solutions to the equation 3m^2-3m-64=-4 ?
The solutions to the equation 3m^2-3m-64=-4 are m=5,m=-4
Find the zeros of 3m^2-3m-64=-4
The zeros of 3m^2-3m-64=-4 are m=5,m=-4