What are the solutions to the equation (d^2)/3-4=0 ?

The solutions to the equation (d^2)/3-4=0 are d=2sqrt(3),d=-2sqrt(3)

Find the zeros of (d^2)/3-4=0

The zeros of (d^2)/3-4=0 are d=2sqrt(3),d=-2sqrt(3)

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\frac{d ^{2}}{3} - 4 = 0

d = 23, d = - 23

Decimal Notation

d = 3.46410 \dots, d = - 3.46410 \dots

Solution steps

\frac{d ^{2}}{3} - 4 = 0

Move

4

to the right side

\frac{d ^{2}}{3} = 4

Multiply both sides by

3

d^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 12, d = - 12

12 = 23

- 12 = - 23

d = 23, d = - 23

x^{2} - 12 x + 32 = 0

(- \frac{1}{( 1 + 6 )}) - (- \frac{1}{( 1 + 1 )})

- 8 = \frac{2}{5} u

x^{2} - 9 x - 90

(3 x - 2) (2 x + 3) = 0

What are the solutions to the equation (d^2)/3-4=0 ?
The solutions to the equation (d^2)/3-4=0 are d=2sqrt(3),d=-2sqrt(3)
Find the zeros of (d^2)/3-4=0
The zeros of (d^2)/3-4=0 are d=2sqrt(3),d=-2sqrt(3)