What are the solutions to the equation (3x-2)(2x+3)=0 ?

The solutions to the equation (3x-2)(2x+3)=0 are x= 2/3 ,x=-3/2

Find the zeros of (3x-2)(2x+3)=0

The zeros of (3x-2)(2x+3)=0 are x= 2/3 ,x=-3/2

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(3 x - 2) (2 x + 3) = 0

x = \frac{2}{3}, x = - \frac{3}{2}

Decimal Notation

x = 0.66666 \dots, x = - 1.5

Solution steps

(3 x - 2) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 2 x + 3 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{3}{2}

(X^{2} - 5 X + 1)^{2} - 11 (X^{2} - 5 X + 1) + 10

x (x - 13) + 40 = 0

3 x^{3} + 21 x^{2} - 54 x

y^{2} + y + 6 = 0

∣ x - 2 ∣ + ∣ x + 1 ∣ = - 1

What are the solutions to the equation (3x-2)(2x+3)=0 ?
The solutions to the equation (3x-2)(2x+3)=0 are x= 2/3 ,x=-3/2
Find the zeros of (3x-2)(2x+3)=0
The zeros of (3x-2)(2x+3)=0 are x= 2/3 ,x=-3/2